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How to use Modulus Operator?
While writing the following code for general arthematic operators, I ran the code with an error (which I later found & also marked below).Surprisingly, without showing an error, the compiler gave an output, which is very odd and absurd.FYI, I ran the code on repl.it. How did it even take the value of 'b'? On what basis it produced the outputs?#include <stdio.h>int main(){ int a,b; float sum,diff,prod,quo;int rem;<span style="background-color: rgb(250, 250, 250);"> printf("Enter the value of 'a': ");</span> scanf("%d",&a); printf("Enter the value of 'b': ");scanf("%d",&a); -->Here, I had an error. Instead of 'b', I typed 'a'.sum= a + b;diff= a-b;prod= a * b;quo= (float) a/b;rem= a % b; printf("\n");printf("The sum of a & b is %.2f\n",sum); printf("\n"); printf("The difference of a & b is %.2f\n",diff); printf("\n");printf("The product of a & b is %.2f\n",prod);printf("\n"); printf("The quotient when a is divided by b is %.2f\n",quo);printf("\n");printf("The remainder when a is divided by b is %d\n",rem);return 0;
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Outline:-Arithmetic Operators -Addition Operator --nuksa: a + b -Subtraction Operator --nuksa: a - b -Multiplication Operator --nuksa: a * b -Division Operator --nuksa: a / b -Modulus Operator --nuksa: a % b
-Arithmetic Operators -Addition Operator --nuksa: a + b -Subtraction Operator --nuksa: a - b -Multiplication Operator --nuksa: a * b -Division Operator --nuksa: a / b -Modulus Operator --nuksa: a % b
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